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Hello Michel,
<p>I've looked at the PSD_monitor_4PI, used to generate the detector image,
and it seems that it computes the horizontal angle
<p>phi = atan2(z,x);
<p>but
<p>phi = atan2(x,z);
<p>would probably be better, as it is the deviation angle of x transversal
coordinate w/r to z propagation axis.
<br>Then, it is straightforward to see that the 1st expression is shifted
by 90 degrees w/r to the 2nd one.
<br>This is not a 'bug' but just the way the angle origin is defined in
this monitor. It will be corrected in the next release.
<p>Emmanuel.
<p>Michel Ain wrote:
<blockquote TYPE=CITE>Hello,
<br>I'm examining the plot of vanadium-example.intr with ROT set to 0,
and I
<br>don't see why the intensity appears on the right side of the figure.
I'm
<br>expecting it symetrically, on the both far left and right sides of
the
<br>figure. I could very welll agree with the representation shown on the
<br>front page of mcstas site.
<br>Cordially
<br>michel Ain
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<pre>--
What's up Doc ?
--------------------------------------------
Emmanuel FARHI, <A HREF="http://www.ill.fr/tas/people/Farhi.html">http://www.ill.fr/tas/people/Farhi.html</A> \|/ ____ \|/
CS-Group ILL4/156, Institut Laue-Langevin (ILL) Grenoble ~@-/ oO \-@~
6 rue J. Horowitz, BP 156, 38042 Grenoble Cedex 9,France /_( \__/ )_\
Work :Tel (33/0) 4 76 20 71 35. Fax (33/0) 4 76 20 76 48 \__U_/</pre>
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