[neutron-mc] vanadium-example.intr

[Emmanuel Farhi]

Hello Michel,

I've looked at the PSD_monitor_4PI, used to generate the detector image,
and it seems that it computes the horizontal angle

phi = atan2(z,x);

but

phi = atan2(x,z);

would probably be better, as it is the deviation angle of x transversal
coordinate w/r to z propagation axis.
Then, it is straightforward to see that the 1st expression is shifted by 90
degrees w/r to the 2nd one.
This is not a 'bug' but just the way the angle origin is defined in this
monitor. It will be corrected in the next release.

Emmanuel.

Michel Ain wrote:

> Hello,
> I'm examining the plot of vanadium-example.intr with ROT set to 0, and I
> don't see why the intensity appears on the right side of the figure. I'm
> expecting it symetrically, on the both far left and right sides of the
> figure. I could very welll agree with the representation shown on the
> front page of mcstas site.
> Cordially
> michel Ain
>
> _______________________________________________
> neutron-mc mailing list
> neutron-mc at neutron.risoe.dk
> http://neutron.risoe.dk/mailman/listinfo/neutron-mc

--
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Emmanuel FARHI, http://www.ill.fr/tas/people/Farhi.html   \|/ ____ \|/
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